Caution: date_parse expects months 1..12 only.
date_parse("13/1/5769") for month=13, Ehul in Jewish calendar, results in month==3 instead of month==13.
It does, however, report the error array showing "Unexpected Character."
It would be nice if date_parse could handle the months properly (just report back a "13" for the month). The older approach of substr() is my workaround.
date_parse
(PHP 5 >= 5.1.3)
date_parse — Returns associative array with detailed info about given date
Beskrivelse
array date_parse
( string $date
)
Returneringsværdier
Returns array on success or FALSE on failure.
Eksempler
Example#1 A date_parse() example
<?php
print_r(date_parse("2006-12-12 10:00:00.5"));
?>
Ovenstående eksempel vil udskrive:
Array ( [year] => 2006 [month] => 12 [day] => 12 [hour] => 10 [minute] => 0 [second] => 0 [fraction] => 0.5 [warning_count] => 0 [warnings] => Array() [error_count] => 0 [errors] => Array() [is_localtime] => )
date_parse
alan at wilcoxengineering dot com
14-Aug-2009 06:02
14-Aug-2009 06:02
gpayne at galenaparkisd com
29-Sep-2007 11:52
29-Sep-2007 11:52
Careful - date_parse is perfectly happy with something like this:
date_parse("2006-2-31");
